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选数(NOIP2002)
deadrain 发表于 2007-08-15 21:56:13
easy! 的说~ ^^
CODE:
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CODE:
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program p1128;
var
n,k,i,s:integer;
a:array[1..20] of longint;
procedure judge(sum:longint);
var
i:longint;
begin
if sum<2 then exit;
if sum>2 then
for i:=2 to trunc(sqrt(sum)) do
if sum mod i=0 then exit;
inc(s);
end;
procedure search(st,k:integer;sum:longint);
var i:integer;
begin
if k=0 then begin judge(sum);exit;end;
for i:=st to n-k+1 do
search(i+1,k-1,sum+a[i]);
end;
begin
readln(n,k);
for i:=1 to n do
read(a[i]);
s:=0;
search(1,k,0);
writeln(s);
end.
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